力扣每日一题2239

题目描述：

思路：遍历，基础没什么多说的

package January;


/**
 * @author hxw
 * @version 1.0
 * @date 2025/1/20 21:03
 * @description: 2239. 找到最接近 0 的数字 简单
 */
public class twenty {
    public static void main(String[] args) {
        int[] nums = {-4, -1, 1, 2, 3};
        int result = Solution.findClosestNumber(nums);
        System.out.println(result);

    }

    class Solution {
        public static int findClosestNumber(int[] nums) {
            int result = nums[0];
            for (int num : nums) {
                if (Math.abs(num) < Math.abs(result) || (Math.abs(num) == Math.abs(result) && num > result)) {
                    result = num;
                }
            }
            return result;
        }

    }
}