力扣每日一题3065

题目描述：

解析：直接循环小于k的即为答案

package January;

/**
 * @author hxw
 * @version 1.0
 * @date 2025/1/14 22:35
 * @description: 3065. 超过阈值的最少操作数 I 简单
 */
public class fourteen {
    public static void main(String[] args) {
        int result = Solution.minOperations(new int[]{2, 11, 10, 1, 3}, 10);
        System.out.println(result);
    }

    class Solution {
        public static int minOperations(int[] nums, int k) {
//        记录nums中小于k的所有
            int count = 0;
            for (int num : nums) {
                if (num < k) {
                    ++count;
                }
            }
            return count;
        }
    }
}